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		Example CD7-4 Derive a Rate Law For Non-Competitive Inhibition
		Solve for the concentrations of the complexes (IE) and (IES) in terms of the free enzyme concentration, (E), and substrate concentration, (S), in a manner similar to that for (ES); substitute these expressions in the total enzyme balance and then obtain the rate law for noncompetitive inhibition. (Let Ks, KI,,and represent the equilibrium constants for reactions 1 through 4, respectively.)
		Solution
		For reaction 2,
		(EI) =KI (I)(E)	(CDE7-4.1)
		We can use either Equation (CD7-19),
			(CDE7-4.2)
		or (CD7-20),
			(CDE7-4.3)
		to express IES in terms of IE, and S. The mole balance on the total amount of enzyme, bound and free (E), is
		Et = E + ES + IE + IES	(CDE7-4.4)
		Substituting Equations (CD7-24), (CDE7-4.1), and (CDE7-4.2) into (CDE7-4.4) and rearranging gives us
			(CDE7-4.5)
		The rate of formation of the product for a noncompetitive inhibition of an enzymatic reaction is
			(CDE7-4.6)