To find the needed cross sectional areas and lengths :

Scenario 1 : Length = 100 dm, Volume = 200 dm³

A_c : 2 dm²
Length : 100dm

Conversion : 0.91

Scenario 2 : Diameter = 4 dm, Length = 10 dm

A_c : 12.6 dm²
Length : 10 dm

Conversion : 0.81

Scenario 3 : Diameter = 0.5 dm, Length = 300 dm

A_c : 0.20 dm²
Length : 300 dm

Conversion : 0.59

Scenario 4 : Length = 25 dm (X4), Total Volume = 150 dm³

A_c : 1.5 dm²
Length : 25

Conversion : 0.85

 Back to part 1 of solution  Back to problem statement

---

CRE > Thoughts > Ten Types > Heterogeneous Example 5 

---