Example 10-3 Fixed-Bed Reactor Design |POLVER05_0
d(X)/d(w) = -rt/FTo #
FTo = 50 #
k = .00087 #
KT = 1.038 #
KB = 1.39 #
alpha = 0.000098 #
Po = 40 #
PTo = 0.3*Po #
y = (1-alpha*w)^0.5 #
P = y*Po #
PH2 = PTo*(1.5-X)*y #
PB = PTo*X*y #
PT = PTo*(1-X)*y #
rt = -k*PT*PH2/(1+KB*PB+KT*PT) #
RATE = -rt #
w(0)=0
X(0)=0
w(f)=10000