ChemChat

1HNMR Correlation


Molecule 49

1H NMR (400 MHz, CDCl3) δ 6.70 (d, J = 10.1 Hz, 1H), 5.93 (d, J = 10.1 Hz, 1H), 4.65 (d, J = 11.9 Hz, 1H), 4.28 (d, J = 1.6 Hz, 1H), 4.21-4.04 (m, 1H), 2.98 (d, J = 1.2 Hz, 1H), 2.93 (dd, J = 14.8, 4.0 Hz, 1H), 2.48-2.23 (m, 2H), 2.13 (tt, J = 3.9, 2.2 Hz, 1H), 1.81-1.63 (m, 2H), 1.44 (s, 3H), 1.37 (s, 3H), 1.34 (s, 3H)

NMR δppm Splitting pattern Integration J(Hz) Chat Forum
Ha 1.34 s 3H The three protons in either of the three methyl group are homotopic with no neighbors that are less than 3 bond distance away, thus they only have a single peak with an integration of 3.
Note: Without given coupling constants, the chemical shifts of Ha and Hb are indistinguishable due to their similar chemical environment.
Hb 1.37 s 3H
Hc 1.44 s 3H   The three homotopic protons in this methyl group are more deshielded than the Ha and Hb because they are 2 bond distance away from the electronegative O atom. The protons only emit a single peak because there is no neighbors that are less than 3 bond distance away from this methyl group.
Hd 1.63-1.81 m 2H   Although these two protons (exo and endo) are diastereotopic, it is hard to differentiate the two due to their similar chemical environment. Compare to Hf exo-endo pair, the Hd exo-endo pair is further from the electronegative region (C=C and ester) of the molecule, thus is expected to have a lower chemical shift than its comparative.
He 2.13 tt (possible alternative: ddd) 1H J=3.9, 2.2 Hz (may be missing a J~3-6Hz) This proton has four 2-bond neighbors: Hd exo-endo pair and Hg exo-endo pair. Presumably, only coupling between He and Hg(exo) (J=3.9Hz) and Hd(exo) (J=3~6Hz) that are equatorial to the ring are observable. Considering He and Hh may constitute a W pattern, it is also possible that He couples with Hh despite they are 4 bond apart (J=2.2Hz).
Hf 2.23-2.48 m 2H These two protons are diastereotopic: one is in the exo and one is in the endo configuration. It is, however, hard to distinguish them without assignable coupling constants. Theoretically, the Hf exo-endo pair may couple with one another and with the Hd exo-endo pair, resulting in a ddd splitting pattern. However, only Hf(endo) may couple with Hh, if a 4-bond W-pattern coupling is possible.
Hg(exo) 2.93 dd 1H J=14.8, 4.0Hz Hg(exo) couples with its endo counterpart (J=14.8Hz) and He (J=4.0Hz).
Hg(endo) 2.98 d 1H J=1.2 Hz (possible alternative: 14.8Hz) Unlike Hg (exo), the coupling between Hg (endo) and He is not observable (J~0Hz), leaving it with only a 2-bond neighbor Hg (exo). The coupling constant should be 14.8Hz rather than 1.2 Hz because the exo-endo pair are geminal protons.
Hh 4.04-4.21 m (possible alternative: dd) 1H Hi is deshielded by the O atom and has a chemical shift around 4ppm. To be more exact, the splitting pattern should be dd because Hh forms two W pattern with two of its 4-bond neighbors He and Hf(endo).
Hi 4.28 d 1H J=1.6HZ (possible alternative 11.9Hz) Analogous to the proton in methyl acetate, which typically carries a chemical shift around 4.2ppm, Hj and Hk have similar peaks at 4.28 and 4.65ppm. Hj couples with Hk and should have a coupling constant of 11.9Hz since they are geminal at the same carbon of the ring. Note:The chemical shifts 4.28 and 4.65ppm are not definite and may be exchanged between Hj and Hk since both protons share similar chemical environment and splitting pattern.
Hj 4.65 d 1H J=11.9Hz
Hk 5.93 d 1H J=10.1Hz This proton has a lower chemical shift than Hl because the electrons on the double bond may delocalize and relocate at the sp2C carrying Hk and push the C=O to the O atom. The doublet signifies Hk’s 3-bond neighbor Hl.
Hl 6.70 d 1H J=10.1Hz This proton is more de-shielded than Hk because of resonance between the conjugated C=C and C=O. The formation of an enolate makes the sp2C farther from the O partially positive. This resonance contributes to deshielding of Hl. The doublet signifies Hl’s 3-bond neighbor Hk.