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Trying a CSTRLet's try a CSTR. The mole balances for CSTR give:cA-cA0 = (-k1cA + k2cB - k4cA2)t The space time of the CSTR is given by t. The equations describing the CSTR result in a set of algebraic equations that must be solved simultaneously for a given space time. We can now plot the different products for various space times.
![]() Again we can write the equations in vector notation:
Notice that the vector containing the kinetics is the same as that for a PFR.
We can more easily compare the productions of B versus the consumption of A for the PFR and CSTR by constructing a state-space plot. In the system we are considering, the state of the system is characterised by the concentrations of A and B. This is because we are not interested in the space time of the reactors but in the selectivity of B.
![]() Lets do some comparisons of these two reactors. If we had a PFR of space time of t = 0.023s and a CSTR of space time t = 0.078s, which should we use? To work this out we use the graphs of the PFR profile and the CSTR products. A comparison is given in the table below:
So for a conversion of A of 0.7 it is better to use a CSTR that a PFR. You should be able to easily see this by looking at the plots of cB versus cA for the PFR and CSTR.
What if we had a PFR of space time 0.057s and a CSTR of space time 0.38s, which should we use? This time we get the following:
So for a conversion of A of 0.85 it is better to use a PFR that a CSTR. Again, you should be able to check this on the differnt plots. Let's have a closer look at the plot state-space plot of cB versus cA. The reactor to choose based on the conversion of A is given by the table below:
The most B is produced in a PFR with an effluent concentration of A 0.17 kmol/m3, that is at a conversion of A of 0.83. Thus, out of the PFR and the CSTR, the PFR results in the greatest production of B. Can we do any better that this?
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