12. Steady-State Non-Isothermal Reactor Design : The Steady State Energy Balance and Adiabatic PFR Applications
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1. Applications of the PFR/PBR User Friendly Energy Balance Equations
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NOTE: The PFR and PBR formulas are very similar.
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If we include pressure drop: |
C. 
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Note: the pressure drop will be greater for exothermic adiabatic reactions than it will be for isothermal reactions |
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Balance on Heat Exchanger Coolant
Solve simultaneously using an ODE solver (Polymath/MatLab). If Ta
is not constant, then we must add an additional energy balance on
the coolant fluid: |
Co-Current Flow |
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Counter-Current Flow |
with Ta = Tao at W = 0 |
For an exothermic reaction: with counter current heat exchange
A Trial and Error procedure for counter current flow problems is required to find exit conversion and temperature.
- Consider an exothermic reaction where the coolant stream enters at the end of the reactor at a temperature Ta0, say 300 K.
- Assume a coolant temperature at the entrance (X = 0, V = 0) to the reactor Ta2 =340 K.
- Calculate X, T, and Ta as a function of V. We can see that our guess of 340 K for Ta2 at the feed entrance (X = 0) gives a coolant temperature of 310 K, which does not match the actual entering coolant temperature of 300 K.
- Now guess a coolant temperature at V = 0 and X = 0 of 330 K. We see that the exit coolant temperature of Ta2 = 330 K will give a coolant temperature at V = V1 of 300 K.
12.1A ↔ B Liquid Phase Adiabatic
12.2A ↔ B Liquid Phase Constant T
a
12.3A ↔ B Liquid Phase Variable T
a, Co-Current
12.4A ↔ B Liquid Phase Variable T
a, Counter Current
12.1
Sketch the Ambient Temperature as a function of V.
12.2
Elementary Liquid Phase Reaction
12.5
Exothermic, Reversible Reaction
12.6
Adiabatic Reaction in a PBR.
12.7
PBR with heat exchange.
12.8
PBR with heat exchange and variable coolant flow rate.
12.3
Nonisothermal Reactions.

Variable Coolant Temperature.
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All chapter references are for the 1st Edition of the text Essentials of Chemical Reaction Engineering
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