H-NMR

Walt is doing a batch test to make sure that his meth is pure and would be the best on the streets. He made Jesse to do a quick H-NMR spectrum to check the quality. Here are the results:

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Signal (ppm)	Explanation
1.44	integration and splitting match well with the N-boc protecting group, the shift is also characteristic of methyl groups.
2.43	This lower signal can be attributed to them being on a Sp3 carbon. Furthermore, they are a doublet because they are near one hydrogen located three bonds away. This peak was also decided based on the integration of two hydrogens.
2.47 - 2.83	This integration is of 5H’s yet it interpreted to be 6H’s. There is a very large cluster of hydrogens in this range. These hydrogens were assigned to this multiplet cluster because they are on Sp3 carbons and have many neighbors.
2.84 - 2.89	This Hydrogen was decided because of its one hydrogen integration as well as its lower signal which would correspond to a hydrogen on a Sp3 carbon. It experiences a increased signal because it is near an oxygen.
3.09 - 3.14	Although very similar to the hydrogen at 2.84-2.89 ppm, it has a larger signal because it is on the side of the molecule which contains the Nitrogen and oxygen five membered ring. This would increase the signal slightly.
3.55	This signal corresponds to hydrogens on a methyl near an oxygen. Peak was decided because of the 6 hydrogen integration.
3.90	Integration and splitting match well to its place. The hydrogen is split by the nitrogen and the two hydrogens next to it, thus it is a triplet. It has a higher integration because it is near the nitrogen.
4.4	This hydrogen was decided based off of its one hydrogen integration and its higher signal. It has a high signal because it is near the nitrogen and oxygen in the five membered ring. Furthermore, it is a multiplet because it is near two sets of hydrogens that may be diastereotopic.
4.68	These hydrogens were based on their doublet splitting and higher integration because they near an oxygen. They are the only two single hydrogens on a sp2 carbon and near an oxygen.
4.87	These hydrogens were assigned to this peak because they have a higher signal because of their location within the five membered ring near the nitrogen and oxygen. They have a 2 hydrogen integration.
5.07	It was decided because it is a singlet and has an integration of one. It has a high signal because it is located on an Sp2 carbon and is near the Nitrogen in the five membered ring. Yet, it has a lower signal than the similar hydrogen at 5.22 ppm because it is farther from the nitrogen in the five membered ring.
5.22	This hydrogen is nearly indistinguishable from the hydrogen at 5.07 ppm. It was decided because it is a singlet and has an integration of one. It has a high signal because it is located on an Sp2 carbon and is near the Nitrogen in the five membered ring.
7.2	It is believed to be a small peak that is most likely hidden under the CDCL2 peak. Hydrogens on nitrogens typically show up in this range. Substantial shielding, thus it is not a doublet.