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Chapter 11: Nonisothermal Reactor Design: The Steady State Energy Balance and Adiabatic PFR Applications
Second Order Reaction in a CSTR.
The acid catalyzed irreversible liquid phase reaction
A 
B
is carried out adiabatically in a CSTR. The reaction is second order in A. The feed, which is equal molar in water (which contains the catalyst) and A, enters the reactor at a temperature of 52˚C and a total volumetric flow rate of 10 dm3/min. The concentration of A entering the reactor is 4 molar.
a) What is the reactor volume to achieve 80% conversion
b) What conversion can be achieved in a 1000 dm3 CSTR? What is the exit temperature?
Hint 1: What is the combined mole balance, rate law and stoichiometry that gives the reactor value as a function of temperature and conversion?
Hint 2: What is the equation that gives X, solely as a function of t, k, and CA0?
Hint 3: What is the equation that one obtains from the energy balance that gives X as a function of T?
Hint 4: What is the specific reaction rate 3?
Hint 5: What CSTR reactor volume is necessary to achieve 80% conversion?
Hint 1: Sketch the conversion obtained from the mole balance and energy balance as a function of T.
Hint 2: Write a Polymath program to obtain the exit conversion and temperature. Use the output to plot XEB and EMB.
Hint 1
Mole Balance
Hint 2
Let
Hint 3
Energy Balance
For 80% conversion T = 325 + 72.7 = 397.7
Hint 4
Hint 5
Part (b) What conversion can be achieved in a 1000 dm3 CSTR?
Hint 1
The exit temperature and conversion are determined from the intersection of XEB and XMB
Hint 2
We can generate XEB and X vs. T curves by incrementing T and calculating the conversion.
Equation for Figure
